Q:

The zeros of a parabola are 6 and −5. If (-1, 3) is a point on the graph, which equation can be solved to find the value of a in the equation of the parabola?3 = a(−1 + 6)(−1 − 5)3 = a(−1 − 6)(−1 + 5)−1 = a(3 + 6)(3 − 5)−1 = a(3 − 6)(3 + 5)

Accepted Solution

A:
ANSWER[tex]3= a( - 1 +6)( - 1 - 5)[/tex]EXPLANATIONThe equation of a parabola in factored form is [tex]y = a(x + m)(x + n)[/tex]where 'a' is the leading coefficient and 'm' and 'n' are the zeros.From the question, the zeros of the parabola are 6 and −5.This implies that,[tex]m = 6 \: \: and \: \: n = - 5[/tex]We plug in these zeros to get:[tex]y= a(x +6)(x - 5)[/tex]If (-1, 3) is a point on the graph of this parabola,then it must satisfy its equation.We substitute x=-1 and y=3 to obtain:[tex]3= a( - 1 +6)( - 1 - 5)[/tex]The first choice is correct.