MATH SOLVE

2 months ago

Q:
# Suppose that 50 identical batteries are being tested. after 8 hours of continuous use, assume that a given battery is still operating with a probability of 0.70 and has failed with a probability of 0.30. what is the probability that greater than 30 batteries will last at least 8 hours

Accepted Solution

A:

The probability of success is constant = p = 0.7

There are a fixed number of trials = n = 50

The trials are independent.

The sample is a simple random sample.

Thus, the given scenario satisfies all the conditions of a Binomial experiment so we will use Binomial probability to solve this problem.

We are to find the probability that greater than 30 bulbs will last atleast 8 hours.

So, we are to find P(X > 30)

We can use any Binomial calculator to find this value.

P(X> 30) comes out to be 0.9152

Therefore, the probability that greater than 30 batteries will last at least 8 hours is 0.9152.

There are a fixed number of trials = n = 50

The trials are independent.

The sample is a simple random sample.

Thus, the given scenario satisfies all the conditions of a Binomial experiment so we will use Binomial probability to solve this problem.

We are to find the probability that greater than 30 bulbs will last atleast 8 hours.

So, we are to find P(X > 30)

We can use any Binomial calculator to find this value.

P(X> 30) comes out to be 0.9152

Therefore, the probability that greater than 30 batteries will last at least 8 hours is 0.9152.